tolong jawab ya pake cara ntah knp sekarang branly susa bgt gada yg mau ngejawab soal soal gw:(
[tex] \frac{ \sqrt{6} }{3 - 2 \sqrt{3} } =\frac{ \sqrt{6} }{3 - 2 \sqrt{3} } \times \frac{3 + 2 \sqrt{3} }{3 + 2 \sqrt{3} } = \frac{ \sqrt{6} (2 + \sqrt{3}) }{9 - 12} = \frac{2 \sqrt{6} + \sqrt{18} }{ - 3} = \frac{2 \sqrt{6} + 3 \sqrt{2} }{ - 3} = - \frac{2}{3} \sqrt{6} - \sqrt{2} [/tex]
[tex] \frac{ \sqrt{6} }{3 - \sqrt{2} } = \frac{2 \sqrt{6} + 3 \sqrt{2} }{ - 3} = - \frac{2}{3} \sqrt{6} - \sqrt{2} = - \sqrt{2} ( \sqrt{3} + 2)[/tex]
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